** what is the intersection of two sets:-**

intersection of two sets is the set in which only those element is present which are present in both set A and set B.

if A={1,2,3,4,1} and B={1,2,5,6} are two sets then intersection of A and B is:-

A∩B={1,2}

**Program:-**

#include<stdio.h>

int main()

{

int a[100],b[100],c[100],n1,n2,n,k=0,i,j;

// taking input of set A

printf("Enter number of element of set A\n");

scanf("%d",&n1);

printf("Enter elements of set A\n");

for(i=0;i<n1;i++)

scanf("%d",&a[i]);

// taking input set B

printf("Enter number of element of set B\n");

scanf("%d",&n2);

printf("Enter elements of set B\n");

for( i=0;i<n2;i++)

scanf("%d",&b[i]);

// Logic for intersection

for( i=0;i<n1;i++)

{

for(j=0;j<n2;j++)

{

if(a[i]==b[j])

{

c[k]=a[i];

k++;

}

}

}

// Printing the elements of intersection of set A and set B

printf("intersection of set A and set B is:-\n");

for(i=0;i<k;i++)

printf("%d ",c[i]);

return 0;

}

**Output:- **

Enter number of element of set A

3

Enter elements of set A

1 2 3

Enter number of element of set B

4

Enter elements of set B

1 1 3 4

intersection of set A and set B is:-

1 3

## 3 Comments

Can you explain how did you do it that your code run and the output is correct?

ReplyDeletewhy not , first you have to know what is intersection of two sets . intersection means finding the elements which are presents in both sets.... so we have to compare the elements of the sets.. So take loop for the set 1 and another loop for set 2 .. after that you have to take a element from set one and compare with elements of set 2 if the element is equal to the any element of the set 2 then store it in the new array . after that at the end you just have to print this new array ...........that's all

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