pattern printing

You are required to form a matrix of size $r\times c$ where $r$ is the number of rows and $c$ is the number of columns. You are required to form the waves of numbers around the provided center, $(C_i,C_j)$ (0-based indexing).
Example:

• Size of the matrix: $r=9$ and $c=9$
• Center coordinates: $C_i=4$ and $C_j=4$ (0 based indexing)
• Pattern:

            4 4 4 4 4 4 4 4 4
            4 3 3 3 3 3 3 3 4
            4 3 2 2 2 2 2 3 4
            4 3 2 1 1 1 2 3 4
            4 3 2 1 0 1 2 3 4
            4 3 2 1 1 1 2 3 4
            4 3 2 2 2 2 2 3 4
            4 3 3 3 3 3 3 3 4
            4 4 4 4 4 4 4 4 4

You are given the values of $r,c,C_i,C_j$ (the values of $C_i$ and $C_j$ is 0-based indexed). Your task is to print the provided pattern.
Input format
The first line contains four integers $r$, $c$, $C_i$, and $C_j$ denoting the number of rows, number of columns, $x$ coordinate of center, and $y$ coordinate of center.
Output format
Print the pattern for the provided input.
Constraints
$$\begin{gathered} 1\le r\le 1e3 \\ 1\le c\le 1e3 \\ 0\le C_i<r \\ 0\le C_j<c \end{gathered}$$

SAMPLE INPUT

10 10 5 5

SAMPLE OUTPUT

5 5 5 5 5 5 5 5 5 5 
5 4 4 4 4 4 4 4 4 4 
5 4 3 3 3 3 3 3 3 4 
5 4 3 2 2 2 2 2 3 4 
5 4 3 2 1 1 1 2 3 4 
5 4 3 2 1 0 1 2 3 4 
5 4 3 2 1 1 1 2 3 4 
5 4 3 2 2 2 2 2 3 4 
5 4 3 3 3 3 3 3 3 4 
5 4 4 4 4 4 4 4 4 4 

Explanation

Given input have shown output.

solution:-

#include<stdio.h>

#include<stdlib.h>

void main()

{

    int r,c,a,b,i,j,k,l,m,n,p=0;

    scanf("%d%d%d%d",&r,&c,&a,&b);

    for(i=0;i<=r-1;i++)

    {

        for(j=0;j<=c-1;j++)

        {

            if(i==a&&j==b)

             printf("%d ",p);

            else

            {

                l=abs(a-i);

                k=abs(b-j);

                m=p+l;

                n=p+k;

                if(l>=k)

                {

                    if(m>=0)

                     printf("%d ",m);

                    else printf("0 ");

                }

                else

                {

                    if(n>=0)

                     printf("%d ",n);

                    else

                     printf("0 ");

                }

            }

            

        }

        printf("\n");

    }

}