Problem:-
Given a sting Str, which contains numbers (0 to 9) and also letters of the English alphabet ( 'a' to 'z' and 'A' to 'Z'). The task is to reverse the string such a way that the positions of numbers in the string are left unaltered.
Example 1:
Input:
a1b2igh3-Value of Str
Output:
h1g2iba3
Explanation:
Without changing the positions of 1, 2 and 3, only the positions of characters 'h', 'g. 'i, 'b' and 'a' have been reversed.
Example 2:
Input:
Ab5c7de96 -- Value of Str
Output:
ed5c7bA96
Code(C++):-
#include<bits/stdc++.h>using namespace std;int main(){ string str; cin>>str; int l=0,r=str.length()-1; while(l<r) { if(str[l]>='0' && str[l]<='9') l++; if(str[r]>='0' && str[r]<='9') r--; char tem=str[l]; str[l]=str[r]; str[r]=tem; l++; r--; } cout<<str; return 0;}
#include<bits/stdc++.h>
using namespace std;
int main(){
string str;
cin>>str;
int l=0,r=str.length()-1;
while(l<r)
{
if(str[l]>='0' && str[l]<='9')
l++;
if(str[r]>='0' && str[r]<='9')
r--;
char tem=str[l];
str[l]=str[r];
str[r]=tem;
l++;
r--;
}
cout<<str;
return 0;
}
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