__ Problem:-__

#### A Power Pokemon Couple is a pair of pokemons with a sum of their power levels equal to a power of two.

#### You are given an array **power**, containing the power levels of many pokemons. You can pick any two to make a power couple.

#### Print the number of such power pokemon couples you can form using the given array.

**Note**: Pokemons with different indices are considered different even if they have the same power level. Since the answer can be huge, print it modulo 10^9 + 7

##### Input Format:

##### Constrains:

##### Sample Input 1:

##### Sample Output 1:

##### Explanation:

##### Sample Input 2:

##### Sample Output 2:

__Solution:-__

#include <bits/stdc++.h>

using namespace std;

int main()

{

//Write your code here

int n;

cin>>n;

int arr[n];

for(int i=0;i<n;i++)

cin>>arr[i];

int count=0;

for(int i=0;i<n;i++)

{

for(int j=i+1;j<n;j++)

{

int a=arr[i]+arr[j];

if(ceil(log2(a))==floor(log2(a)))

count++;

}

}

cout<<count;

}

#include <bits/stdc++.h>

using namespace std;

int main()

{

//Write your code here

int n;

cin>>n;

int arr[n];

for(int i=0;i<n;i++)

cin>>arr[i];

int count=0;

for(int i=0;i<n;i++)

{

for(int j=i+1;j<n;j++)

{

int a=arr[i]+arr[j];

if(ceil(log2(a))==floor(log2(a)))

count++;

}

}

cout<<count;

}

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