Write a function that return sum of all the odd digits of a given positive no entered through keyboard in Python
Given a number , write a function that return sum of all the odd digits of a given positive no entered through keyboard in Python .
Sample input
4567
Sample Output:
Sum of odd digits of 4567 is: 12
Write a function that return sum of all the odd digits of a given positive no entered through keyboard in Python
The objective of the code is to write a function that return sum of all the odd digits of a given positive number entered by the user .
Algorithm:-
- Define a function that takes an integer as input.
- Initialize a variable sum to 0.
- Convert the integer to a string.
- Traverse the string, check if each character is an odd digit or not.
- If it is an odd digit, convert it back to an integer and add it to the sum.
- Return the sum.
Code(Python):-
def sum_of_odd_digits(num):
sum = 0
str_num = str(num)
for digit in str_num:
if int(digit) % 2 != 0:
sum += int(digit)
return sum
# Driver code to test the function
num = int(input("Enter a positive integer: "))
print("Sum of all the odd digits of", num, "is", sum_of_odd_digits(num))
Output:-
Enter a positive integer: 4567
Sum of all odd digits of 4567 is 12
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