C Program to check whether a number is Armstrong or not.

C Program to check whether a number is Armstrong or not

Given a number , write a program to check that given number is Armstrong or not . So for that first we have to know that what is Armstrong number .

What is Armstrong number:-  Click here   

Sample input

153

Sample output

Armstrong number 

C Program to check whether a number is Armstrong or not

The objective of the code is to check whether a number is Armstrong or not .

Code(C):-

#include<stdio.h>

#include<conio.h>

int main()

{

int n,n1,n2,r,s=1,sum=0; //r=reminder

printf("Enter a number");

scanf("%d",&n);

n1=n;

n2=n;

while(n!=0)

{

r=n%10;

n=n/10;

while(n1!=0)

{

s=s*r;

n1=n1/10;

}

sum=sum+s;

s=1;

n1=n2;

}

if(sum==n2)

printf("number is Armstrong");

else

printf("number is not Armstrong");

return 0;

}

Output:-

Enter a number

153

number is Armstrong

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