You work as an engineer. You were given an empty board with $\ufffd$ consecutive cells; at any moment, each cell can display one character.

You want the board to display a string $\ufffd$ with length $\ufffd>\ufffd$. Since the board isn't large enough, you want to display the string in $\ufffd-\ufffd+1$ steps. In the $\ufffd$-th step ($1\le \ufffd\le \ufffd-\ufffd+1$), you'll make the board display the characters ${\ufffd}_{\ufffd},{\ufffd}_{\ufffd+1},\dots ,{\ufffd}_{\ufffd+\ufffd-1}$.

The power required to switch the board from step $\ufffd$ to step $\ufffd+1$ (for $1\le \ufffd\le \ufffd-\ufffd$) is equal to the number of characters displayed on the board that have to change between these steps. You should find the total power required for the whole process of displaying a string, i.e. the sum of powers required for switching between all consecutive pairs of steps.

### Input

- The first line of the input contains a single integer $\ufffd$ denoting the number of test cases. The description of $\ufffd$ test cases follows.
- The first line of each test case contains two space-separated integers $\ufffd$ and $\ufffd$.
- The second line contains a single string $\ufffd$ with length $\ufffd$.

### Output

For each test case, print a single line containing one integer — the total power required for text switching.

### Constraints

- $1\le \ufffd\le 1,000$
- $2\le \ufffd\le 1{0}^{5}$
- $1\le \ufffd<\ufffd$
- each character of $\ufffd$ is a lowercase English letter
- the sum of $\ufffd$ for all test cases does not exceed $1{0}^{6}$

### Subtasks

Subtask #1 (20 points):

- $1\le \ufffd\le 100$
- $2\le \ufffd\le 50$

Subtask #2 (80 points): original constraints

### Sample 1:

3 6 3 aabbcc 5 2 abccc 4 3 aabb

4 3 1

### Explanation:

Example case 1:

- In step $1$, the board is displaying "aab".
- In step $2$, the board is displaying "abb".
- In step $3$, the board is displaying "bbc".
- In step $4$, the board is displaying "bcc".

The power required for switching from the $1$-st to the $2$-nd step is $1$, because cell $1$ changes from 'a' to 'a' (requiring power $0$), cell $2$ changes from 'a' to 'b' (requiring power $1$) and cell $3$ changes from 'b' to 'b' (requiring power $0$); $0+1+0=1$.

The power required for switching between the $2$-nd and $3$-rd step is $2$ and the power required for switching between the $3$-rd and $4$-th step is $1$.

Therefore, the answer is $1+2+1=4$.

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